What's The Balanced Equation Of The Combustion Of Liquid Butane (C4H10)?

C4H10 + O2 -> CO2 + H2O

Balancing the equation would result in the following

2C4H10 + 13O2 -> 8CO2 + 10H2O

C4H10(l) + O2(g) ® CO2(g) + H2O(g)

Balance atoms in complex substances first

4 == C == 1 x 4 •C4H10(l) + O2(g)  4 CO2(g) + H2O(g) •10 == H == 2 x 5 •C4H10(l) + O2(g)  4 CO2(g) + 5 H2O(g)

Balance free elements by adjusting coefficient in front of free element

13/2 x 2 == O == 13 •C4H10(l) + 13/2 O2(g)  4 CO2(g) + 5 H2O(g)

If fractional coefficients, multiply thru by denominator

{C4H10(l) + 13/2 O2(g)  4 CO2(g) + 5 H2O(g)}x 2

The Balanced Equation is:
2 C4H10(l) + 13 O2(g)  8 CO2(g) + 10 H2O(g)