How Many Anions Are There In 2.50 G Of MgBr2?

2 Answers

John McCann answered

2.50 grams MgBr2 (1 mole MfBr2/184.11 grams)(2 mole Br/1 mole MgBr2)(6.022 X 10^23/1 mole Br)

= 1.64 X 10^22 anions of bromine in 2.50 grams of magnesium bromide
------

Zhu Yugang answered

M(MgBr2)=184 g/mol,n=m/M(MgBr2)=2.5/184=0.0136 mol,the Anions are Br^-,so n(Br^-)=0.0136×2=0.0272 mol.There are 0.0272 mol Anions In 2.50 G Of MgBr2.

Answer Question

Didn't find the answer you were looking for?