An electron moves in a straight line with a constant speed of V = 1.10 X Ten restu 6 M/s which has been measured to a precision of 0.10 percent what is the maximum precision with which its postion could be simultaneously measured?

We will have ti use the Heisenberg's uncertainty principle in this problem. So we have

Dp. Dx >= h/4*pi

where Dx denotes uncertainty in position and Dp the uncertainty in momentum.

=> Dx >= h / (4 * pi * m* Dv)
where Dv is the uncertainty in velocity.

Dv = (0.10/100) * 1.10 * 10^6 = 1.10 * 10^3 m/s [10^6 means 10 raised to the power 6]

So
Dx >=h / (4 * pi * m* 1.10 * 10^3) = 5.268 * 10^(-8) m

So the min uncertainty in position is is given by Dx which implies maximum precision.

So Dx = 5.268 * 10^(-8) m.