How many molecules are in 43.14 kg NaHCO3?

43.14 kg NaHCO3 (1000 g/1 kg)(1mole NaHCO3/84.008 g)(6.022 X 10^23/1 mole NaHCO3)

= 3.092 X 10^26 molecules NaHCO3

the above answer by Kahadija was incorrect on the exponent, so I assume a small mistake of transposition.

M = 23 + 1.008 + 12.01 + 3*16 = approx 84.
N = m/M = 43.14*1000/84 (gmols)
no of molecules = Avogadro's constant x number of moles = 6.02*10^23*n