You have 18 formula moles but without further info, such as moles/mass of reactants, nothing more can be said about this problem.
How many moles of water are produced in this reaction? 2 C8H18 (g) + 25 O2 (g) ---> 16 CO2 (g) + 18 H2O (g)
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we can use the mole ratios here.
0.390 moles Octane x (25 moles O2 / 2 moles Octane) = 4.9 moles O2 ( needed)
0.63 moles O2 x ( 2 moles octane / 25 moles O2) = 0.0504 moles octane needed
Use amount of O2
0.63 moles O2 x (18 moles H2O / 25 moles O2)
= 0.4536 moles H2O
==> 0.4536 moles H2O produced. <==
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