The cross sectional area is
a = π*r^2 = π*(d/2)^2 = (π/4)*d^2
a = π/4*(15 mm)^2 = 225π/4 mm^2
a = π*r^2 = π*(d/2)^2 = (π/4)*d^2
a = π/4*(15 mm)^2 = 225π/4 mm^2
Determine The Cross Sectional Area Of A Steel Rod With A Diameter Of 15mm And Length Of 3m And Tensile Load Of 10 KN?