If Ice Has A Density Of .92 G/cm3 What Is The Volume Of A 5000 Gram Bag Of Ice?

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Oddman answered
(x cc)*(.92 g/cc) = 5000 g   (write an equation for the problem)
x cc = (5000 g)/(.92 g/cc)   (solve the equation for the unknown)
x cc = (5000/.92) cc = 5434.8 cc

Since the density is given to 2 significant figures, and the weight is given to an undetermined number of significant figures (perhaps only 1), the proper answer to this question is 5400 cc, that is, rounded to 2 significant figures.

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