Use a Punnett Square, heterozygous genotype we can use Tt and homozygous recessive we can use tt (T as a dominant trait and t as a recessive) thus follows:
T t
t Tt tt
t Tt tt
50% Tt and 50% tt, thus your answer is 50% chance of having an offspring with the homozygous recessive phenotype in this case (tt).
T t
t Tt tt
t Tt tt
50% Tt and 50% tt, thus your answer is 50% chance of having an offspring with the homozygous recessive phenotype in this case (tt).