What Would Be The Value Of X In CuSO4 X H2O If The Experiment Was Repeated With 1000 G Of CuSO4 X H2O?"

Cu- 1x63.5 = 63.5   18x / (319.6 + 18x) X 100 = % of water in the Hydrate
S- 1x32.1 =32.1   solve for x and plug it in
O- 4x16=224
H20- Xx18 =18.0x
  =(319.6+18x)