2Fe + 3O2 --> 2Fe2O3
As you can see they, iron and iron (III) oxide are one to one, so 9.6 moles iron (III) oxide produced.
Formal set up.
9.6 moles Fe (2 moles Fe2O3/2 mole Fe)
= 9.6 moles Fe2O3 produced
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2Fe + 3O2= 2Fe2O3. How many mol of Iron 3 oxide would be produced if 9.6 moles of iron reacted?