At what temperature will 0.654 moles of neon gas occupy 12.30 liters at 1.95 atmosphere?

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John McCann Profile
John McCann answered

Ideal gas equation.

PV = nRT

Pressure * volume = moles gas * constant * temperature in Kelvin

PV = nRT

Algebraically manipulated to get temperature.

T = PV/nR

T = (1.95 atm)(12.30 L)/(0.654 moles He)(0.08206 L*atm/mol*K)

T = 447 Kelvin

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