Albert is riding a scooter at a velocity of 80 km/h when he sees an old man crossing the road 45 meter away.He immediately steps hard on the brakes to get the maximum deceleration of 7.5 m/s2. How far will he go before stopping?

A formula of kinematics.

V^2 = Vo^2 + 2ax ( initial velocity falls out of equation )

Change 80 km/hr (1000 meters/1 km)(ihr/3600 s)

= 22.22 m/s

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(22.22 m/s)^2 = 2( 7.5 m/s^2)X

X = 493.7284/15

= 32.9 meters

======( close, but the old man lives! )