S=(1/2)gt^2

3.0=0.5*10*t^2, then, t=0.77s

when the apple just as it reaches the ground, v=gt, v=10*0.77=7.7m/s

so, the kinetic energy is 0.5*0.95*7.7^2=28.16.

3.0=0.5*10*t^2, then, t=0.77s

when the apple just as it reaches the ground, v=gt, v=10*0.77=7.7m/s

so, the kinetic energy is 0.5*0.95*7.7^2=28.16.