An Apple With A Mass Of 0.95 Kilograms Hangs From A Tree Branch 3.0 Meters Above The Ground. If It Falls To The Ground, What Is The Kinetic Energy Of The Apple Just As It Reaches The Ground?

S=(1/2)gt^2
3.0=0.5*10*t^2, then, t=0.77s
when the apple just as it reaches the ground, v=gt, v=10*0.77=7.7m/s
so, the kinetic energy is 0.5*0.95*7.7^2=28.16.