45 Degrees Of Fahrenheit Is Equivalent To How Many Celsius?

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7 Answers

Oddman Profile
Oddman answered
The relationship between temperatures expressed on the Fahrenheit scale and those expressed on the Celsius scale is given by
C = (5/9)(F-32°)

C = (5/9)(45°-32°) = (5/9)*13° = (65/9)° = 7 2/9°
C ≈ 7.2°

45° Fahrenheit is about 7.2° Celsius.
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Numerous calculators are available on the Internet for performing this conversion. Here is one.
Midnite star Profile
Midnite star answered
It's nice to see you read Wikipedia....I should have too, before I answered with an answer I'd been taught, and apparently wrongly. Thank you for the corrections and my apologies to Florcullen. I disagreed with Flyboy because he didn't give an answer. Just a formula.
Anonymous Profile
Anonymous answered
So what is the answer ?
Midnite star Profile
Midnite star answered
Temperature in Celsius is a difference of 32 degrees. Celsius considers the freezing point 0 degrees, against Fahrenheit, at 32 degrees. Therefore, the 45 degree temp would be 45 minus 32, which equals 13 Celsius.
thanked the writer.
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Anonymous
Anonymous commented
That is incorrect. The difference of fahrenheit to celsius is not linear, therefore, simply adding or subtracting 32 degrees will not yield a correct answer. C= (5/9)(F-32) and F = (C+32)(9/5). Also, substituting one-half for 5/9 or two for 9/5 will give an approximate answer if you're trying to do it in your head.
Midnite star
Midnite star commented
I tried to give a simple answer, because we don't know what level of education everyone on this site has. I see you have a bit more than I did in Math, but that doesn't give you the right to be insulting. My answer IS correct.. Even though I came up with it by the old way, I was taught. Did you come up with a different number by doing it your way ? Geez....3 months ago, and your looking for "mistakes" ? What do you do...search every math answer and add your little corrections to them all day?
Anonymous
Anonymous commented
Im sorry Midnite113 but the answer is 7.2 degrees Flyboy09 is correct. Unfortunately you only have half of the equation

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Anonymous