Well, it's hard not to say "It's just the way it is", because it follows a law of Physics, but I'll try to explain the best I can.
Up the electromagnetic spectrum is this order. Radio, Microwave,
Infrared, red, orange, yellow, green, blue, indigo, violet,
ultraviolet, X-ray, and Gamma. The higher up the radiation, the smaller
the wavelength (the length of the wave, intuitively), and the higher
the frequency (the amount of "waving" done in a second).
Since frequency (aforementioned) is directly proportional to Energy
with the equation E=hf (or instead of "f", "v" as wikipedia loves to
call it), it makes sense that the higher the frequency, the higher the
energy per photon. Right?
UV is definitely above infrared in
this case, and has been repeatedly proven through experiments to be on
a higher tier than infrared radiation.
Up the electromagnetic spectrum is this order. Radio, Microwave,
Infrared, red, orange, yellow, green, blue, indigo, violet,
ultraviolet, X-ray, and Gamma. The higher up the radiation, the smaller
the wavelength (the length of the wave, intuitively), and the higher
the frequency (the amount of "waving" done in a second).
Since frequency (aforementioned) is directly proportional to Energy
with the equation E=hf (or instead of "f", "v" as wikipedia loves to
call it), it makes sense that the higher the frequency, the higher the
energy per photon. Right?
UV is definitely above infrared in
this case, and has been repeatedly proven through experiments to be on
a higher tier than infrared radiation.