What mass of silver nitrate (AgNO3) is required to make 250mL of a .125M solution of silver nitrate?


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John McCann Profile
John McCann answered
Molarity = moles of solute/Liters of solution

Let's get moles AgNO3

0.125 M AgNO3 = moles AgNO3/0.250 liters

= 0.03125 moles AgNO3 (169.91 grams/1 mole AgNO3)

= 5.31 grams AgNO3 required

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