Anonymous

What mass of oxygen is needed for the complete combustion of 8.60×10−3 g of methane?

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1 Answers

John McCann Profile
John McCann answered

Do you mean...,

8.60 X 10^(-3)

or

8.60 X 10^3

?

If I do not hear back from you by tomorrow I'll do this simple combustion problem both ways, but you could save me the work by using the proper notation. This...^...means to raise to a power.

======

First the balanced equation,

CH4 + 2O2 --> CO2 + 2H2O

------First, 8.60 X 10^(-3) g

8.60 X 10^(-3) g (1 mole CH4/16.042 g)(2 mole O2/1 mole CH4)(32 g/1 mole O2)

= 0.034 grams oxygen

======Now, 8.60 X 10^3 g

8.60 X 10^3 g (1 mole CH4/16.042 g)(2 mole O2/1 mole CH4)(32 g/1 mole O2)

= 3.43 X 10^4 grams oxygen

======Both ways.


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