Anonymous

Calculate the number of particles in 15.5 g of barium phosphate?

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John McCann answered

Particles? I assume you mean molecules/atoms per mole, or atoms per species. Anyway..., Ba3(PO4)2

15.5 g Ba3(PO4)2 (1 mol Ba3(PO4)2/601.8 g)(6.022 X 10^23/1 mol Ba3(PO4)2)

= 1.6 X 10^22 "particles" of barium phosphate in 15.5 g Ba3(PO4)2

======Now, to find, say, atoms of barium in Ba3(PO4)2

15.5 g Ba3(PO4)2 (1 mole Ba3(PO4)2/601.8 g)(3 mole Ba/1 mol Ba3(PO4)2)(6.022 X 10^23/1 mol Ba)

= 4.7 X 10^22 atoms of barium in 15.5 g Ba3(PO4)2

======And so on, just don't forget the proper molar ratio.

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