Barium chloride reacts with sodium phosphate to form barium phosphate and sodium chloride. The balanced equation for the reaction is;
3BaCl2 + 2Na3(PO4) ------> Ba3(PO4)2 + 6NaCl
Reactants consist of three moles of barium chloride and two moles of sodium phosphate. The products produce during this reaction are precipitates of barium phosphate and six moles of sodium chloride.
3BaCl2 + 2Na3(PO4) ------> Ba3(PO4)2 + 6NaCl
Reactants consist of three moles of barium chloride and two moles of sodium phosphate. The products produce during this reaction are precipitates of barium phosphate and six moles of sodium chloride.