If you mean that the distance between diagonally opposite corners on the square is 14 inches then it is a question of applying Pythagoras' Theorem. Think of the square as being 2 right angled triangles placed together, each having a hypotenuse of 14 inches.
Using Pythagoras (Square of Hypotenuse equal to sum of squares of 2 other sides), firstly, you square the hypotenuse = 14 x 14 = 196.
Thus, the squares of the 2 other sides add up to 196.
As we started with a square shape, we know that each of the other sides are the same length, so each side squared must be 196 / 2 = 98.
Thus the square of each side of the square(shape) is 98.
So, the length of each side is the square root of 98 which is approx 9.9 inches.
Using Pythagoras (Square of Hypotenuse equal to sum of squares of 2 other sides), firstly, you square the hypotenuse = 14 x 14 = 196.
Thus, the squares of the 2 other sides add up to 196.
As we started with a square shape, we know that each of the other sides are the same length, so each side squared must be 196 / 2 = 98.
Thus the square of each side of the square(shape) is 98.
So, the length of each side is the square root of 98 which is approx 9.9 inches.
