What Mass Of Dinitrogen Monoxide, N2O, Contains The Same Number Of Molecules As 3.00 G Of Trichlorofluoromethane, CCl3F? (a)0.106 G (b)1.04g (c)9.37 G (d) 0.961 G

Ok I'm not sure about this ,but I think that’s how it works :
First you find out what is 1 mole of each :
1 mole of N2O = (14*2) + 16 = 44 g
1 mole of CCl3F = 12+ (35 * 3) + 19  = 136 g
Now if 1 mole of CCl3F has 136 g then what number of moles contains 3 g ? Cross multiplication :
1 mole : 136g
X moles : 3 g
Divide 3/136 = 0.022 moles
Now if 0.022 moles of CCl3F contains 3 g the same number of molecules of N2O should =
  0.022 * 44 g = 0.968 g
So, I would go with (g) which is the closest : 0.961 g
Hope that helps………….