3.00 grams CCl3F (1 mole CCl3F/137.36 g)(6.022 X 10^23/1 mole CCl3F molecules)( 1 mole CO2 molecules/6.022 X 10^23)(44.01 grams/1 mole CO2)
= 0.961 grams CO2
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What mass of carbon dioxide, CO2, contains the sam number of molecules as 3.00 g of trichorofluoromethane, CCl3F? How would you solve this?