5.10*101.11=515.661g
515.661/(515.661+4.47*1000)=0.1034.
515.661/(515.661+4.47*1000)=0.1034.
What Is The Molality Of A Solution That Contains 5.10 Mol KNO3 In 4.47 Kg Water? (molar Mass Of KNO3 = 101.11 G/mol)