What Volume Of 18.0 M Sulfuric Acid Must Be Used To Prepare 15.5 L Of 0.195 M H2SO4?

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surendar selvam Profile
surendar selvam answered
1 litre @ 0.50 mol / litre has 0.50 moles of solute

NiCl2 from the salt NiCl2·6H2O whose Formula Weight is 237.71g/mol

0.50 moles @ 237.71g/mol = 118.855 grams

how would you prepare 1.00 L of a 0.50 M ?.... Even though there are
few significant digits requested , I would still weigh out 118.8 grams
of

NiCl2·6H2O , which I would dissolve into some water, & once dissolved I would dilute it up to 1.00 litres

when I weigh out 0.50 moles of NiCl2·6H2O , it gives me 0.5 moles of NiCl2 with a little excess baggage in the form of 6H2O

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Sodium carbonate (with a molar mass of 105.99 g/mol)from the pure solid

0.50 moles @ 105.99 g/ mol = 52.995 grams

how would you prepare 1.00 L of a 0.50 M ?.... Even though there
are few significant digits requested , I would still weigh out 52.0
grams of Na2CO3 , which I would dissolve into some water, & once
dissolved I would dilute it up to 1.00 litres

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