Sulfuric acid dissolves aluminum metal according to the following reaction: 2Al(s)+3H2SO4(aq)--->Al2(SO4)3(aq)+3H2(g) Suppose you wanted to dissolve an aluminum block with a mass of 15.9g.What minimum mass of H2SO4(in grams) would you need?


2 Answers

John McCann Profile
John McCann answered
15.9 grams Al (1 mole Al/26.98 grams)(3 mole H2SO4/2 mole Al)(98.086 grams/1 mole H2SO4)

= 86.7 grams of sulfuric acid minimum

These are just thinking it through problems. You try to get H2 mass and don't forget mole ratios.
Robert Marley Profile
Robert Marley answered
WTH are you talking about? If youre smart enough to write the question yourself, arent you smart enough to answer it?

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