What Is The Percent Yield For The Reaction Of 500. G Of CS2 And Excess O2 If 768. G Of SO2 Was Recovered In The Laboratory?

CS2:12+2*32=76g/mol
500/76=6.58mol
6.58*2*64=842.11g
768/842.11*100%=91.20%
so the percent yield is 91.20%.