What Is The Percent Yield For The Reaction Of 3.74 G Of Na And Excess O2 If 5.34 G Of Na2O2 Was Recovered In The Laboratory?

2 Na  + O2 --> Na2O2
3.74 g Na x  1 mol Na / 23.0g x 1 mol Na2O2 / 2 mol Na   x  78.0g Na2O2 /1 mol Na2O2 =  6.34 g Na2O2 = theoretical yield    5.34 g = actual yield so  5.34/6.34  x 100 = 84.2%