If 5.3g O2 Reacts With Nh3 To Produce 3.1g No2, What Would The Percent Yield Of No2 Be?

4NH3+5O2=4NO2+6H2O
  160    184
  5.3g    x
160/5.3=184/x
x=6.905g
3.1/6.905*100%=44.90%