Fe2O3:160g/mol
34.6/160*2=0.4325mol
there are 0.4325 mole Fe.
34.6/160*2=0.4325mol
there are 0.4325 mole Fe.
The Formula For Rust Can Be Represented By Fe2O3. How Many Moles Of Fe Are Present In 34.6 G Of The Compound?
