N(H2O)=5n(C4H10)=12.5*5=62.5 Moles.
2C4H10 + 13O2 → 8CO2 + 10H2O The Equation Shows The Combustion Of Butane (C4H10). How Many Moles Of Water Can Be Produced By 12.5 Moles Of C4H10 With Excess Oxygen?
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