Given This Equation: C3H8 + 5O2 → 3CO2 + 4H2O, How Many Grams Of CO2 Result When 125 Grams Of C3H8 React ?

Moles C3H8 = 125 / 44.09676 g/mol = 2.83
Moles CO2 = 3 x 2.83 = 8.49
Grams CO2 = 8.49 mol x 44 g/mol = 373.5 g

Moles O2 needed = 5 x 2.83 = 14.15
Grams O2 = 14.15 mol x 32 g/mol = 452.8 g