?
Do you mean...?
N2 + 3H2 --> 2NH3
------Assuming H2 limits.
36.0 g H2 (1 mole H2/2.016 g)(2 mole NH3/3 moleH2)(17.034 g/1 mole NH3)
= 203 grams ammonia produced
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When 36.0 g of H2O react, how many grams of NH3 are produced?
?
Do you mean...?
N2 + 3H2 --> 2NH3
------Assuming H2 limits.
36.0 g H2 (1 mole H2/2.016 g)(2 mole NH3/3 moleH2)(17.034 g/1 mole NH3)
= 203 grams ammonia produced
======
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