General Torque= r*f sin(theta)

T

As distance of F1 is twice of F2 from pivot

T

Net torque=0

T

T

2*20*0.707=F

F

T

_{2}= r*F_{2}Sin(90)^{o}As distance of F1 is twice of F2 from pivot

T

_{1}=2r*F_{1}Sin(45)^{o}Net torque=0

T

_{1}-T_{2}=0T

_{1}=T_{2}2r*F_{1}Sin(45)^{o}= r*F2 Sin(90)^{o}2*20*0.707=F

_{2}F

_{2}=28.28N