N(CaCO3)=400/100=4mole
n(CO2)=n(CaCO3)=4mole.
4*22.4=89.6 liters.
n(CO2)=n(CaCO3)=4mole.
4*22.4=89.6 liters.
How Many Liters Of CO2 Are Produced When 400. G CaCO3 Reacts With HCl In The Following Reaction At STP? CaCO3 + 2 HCl ® CaCl2 + CO2 + H2O