# A solution is formed by mixing 0.03g NaOH with 50.0ml of 0.010M HNO3. What is the PH of the solution?

To ascertain the PH value of a solution, you must first calculate the molarity numbers of each element of the solution and then see which has the stipulation, "excess". To find molarity in excess, use the equation Na Oh mm plus 40 Mol. Equals .03 divided by 40, with an answer of 00075. After you determine, through a subtraction process, which answer is "excess", look for PH by adding Na PH mm plus 40 Mol. You will get an answer of .000075.

• More steps

Then, remember that molarity is really the amount of moles measured per liter of solution, so the formula is: .01 times .050, with an answer of .0005. When you subtract both molarity numbers, you will find that .0025 is in excess of the Na Oh element, so that solution will be classified as the "basis". The PH number will be 11.4.

• Tips

If the explanation provided above seems confusing to you, you probably don't have the basic knowledge and understanding you need to solve for PH of a solution. There are some shortcuts you can take; for example, you may want to use an online calculator that calculates PH. However, if you are planning a career in science or studying this math and science concept at school, you should really know how to solve and set up these types of equations. In other words, you should understand the steps, and be able to show your work.

The only way to learn is through studying and repetition, so spend some time exploring and using formulae for molarity and PH. Keep teaching yourself and augment your study and practice with help from a teacher, professor, or tutor. Over time, you will become more comfortable with calculating the PH of a solution, and you'll be able to use the process to give your experiments and conclusions more accuracy.
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