How Many Moles Of Water Are Required To Produce 2.15 Mole Oxygen Gas In This Reaction?

The decomposition equation for water molecule is;

2H₂O --> 2H₂ + O₂

one mole of oxygen gas produced with moles of water = 2

2.15 moles of oxygen gas produced with moles of water = 2* 2.15

2.15 moles of oxygen gas produced with moles of water = 4.3

4.3 H₂O --> 4.3 H₂ + 2.15 O₂

4.3 moles of water are required to produce 2.15 mole of oxygen gas.