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How Many Moles Of Water Are Required To Produce 2.15 Mole Oxygen Gas In This Reaction?

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amber Jhon answered
The decomposition equation for water molecule is;

2H2O --> 2H2 + O2

one mole of oxygen gas produced with moles of water = 2

2.15 moles of oxygen gas produced with moles of water = 2* 2.15

2.15 moles of oxygen gas produced with moles of water = 4.3

4.3 H2O --> 4.3 H2 + 2.15 O2

4.3 moles of water are required to produce 2.15 mole of oxygen gas.

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