Aluminum sulfate reacts with sodium hydroxide to yield sodium sulfate and aluminum hydroxide.
Al2(SO4)3 ------ > 2Al+3 + 3SO4-2
NaOH ------ > Na+1 + OH-1
Al+3 + 3OH-1 ------ > Al(OH)3
2Na+1 + SO4-2 ------ > Na2SO4
The net ionic equation for the reaction is;
Al2(SO4)3 (aq) + 6NaOH (aq) -----> 3Na2SO4 (aq) + 2Al(OH)3 (s)
One mole of aluminum sulfate combines with six moles of sodium hydroxide to form three moles of sodium sulfate and two moles of aluminum hydroxide.
Al2(SO4)3 ------ > 2Al+3 + 3SO4-2
NaOH ------ > Na+1 + OH-1
Al+3 + 3OH-1 ------ > Al(OH)3
2Na+1 + SO4-2 ------ > Na2SO4
The net ionic equation for the reaction is;
Al2(SO4)3 (aq) + 6NaOH (aq) -----> 3Na2SO4 (aq) + 2Al(OH)3 (s)
One mole of aluminum sulfate combines with six moles of sodium hydroxide to form three moles of sodium sulfate and two moles of aluminum hydroxide.