**C4H10 + O2 -> CO2 + H2O**

Balancing the equation would result in the following

**2C4H10 + 13O2 -> 8CO2 + 10H2O**

Balancing the equation would result in the following

C4H10(l) + O2(g) ® CO2(g) + H2O(g)

Balance atoms in complex substances first

4 == C == 1 x 4 •C4H10(l) + O2(g) 4 CO2(g) + H2O(g) •10 == H == 2 x 5 •C4H10(l) + O2(g) 4 CO2(g) + 5 H2O(g)

Balance free elements by adjusting coefficient in front of free element

13/2 x 2 == O == 13 •C4H10(l) + 13/2 O2(g) 4 CO2(g) + 5 H2O(g)

If fractional coefficients, multiply thru by denominator

{C4H10(l) + 13/2 O2(g) 4 CO2(g) + 5 H2O(g)}x 2

The Balanced Equation is:

2 C4H10(l) + 13 O2(g) 8 CO2(g) + 10 H2O(g)

Balance atoms in complex substances first

4 == C == 1 x 4 •C4H10(l) + O2(g) 4 CO2(g) + H2O(g) •10 == H == 2 x 5 •C4H10(l) + O2(g) 4 CO2(g) + 5 H2O(g)

Balance free elements by adjusting coefficient in front of free element

13/2 x 2 == O == 13 •C4H10(l) + 13/2 O2(g) 4 CO2(g) + 5 H2O(g)

If fractional coefficients, multiply thru by denominator

{C4H10(l) + 13/2 O2(g) 4 CO2(g) + 5 H2O(g)}x 2

The Balanced Equation is:

2 C4H10(l) + 13 O2(g) 8 CO2(g) + 10 H2O(g)

C4H10 + 13/2O2 = 4CO2 + 5H2O

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