0.72
Phosphoric Acid, H3PO4, Is Neutralized By Magnesium Hydroxide, Mg(OH)2, According To The Equation Shown. How Many Moles Of Water Will Be Produced From The Neutralization Of 0.24 Mole Of H3PO4?
2H3PO4+3Mg(OH)2=Mg3(PO4)2+3H2O
n(H2O)=3/2n(H3PO4)=3/2*0.24=0.36mole.
n(H2O)=3/2n(H3PO4)=3/2*0.24=0.36mole.
